Find the tangent equation to the given curve that passes through the point (15,15). Note that due to the t2 in the x equation and the t3 in the y equation, the equation in the parameter thas more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point: x=9t2+6y=6t3+9​ (tangent at smaller t ) (tangent at larger t)