Put the differential equation 6 ′=2 36 into the form ′ ()=() and find () and ().

a) f(x) = 3x² + C; f(x) = x³ + C
b) f(x) = 2x³ + C; f(x) = x² + C
c) f(x) = x² + C; f(x) = 3x² + C
d) f(x) = x³ + C; f(x) = 2x³ + C