A mixture consisting of 0.150 mol H₂ and 0.150 I2 is brought to equilibrium at 445 °C, in a 3.25 L flask. Calculate the equilibrium amounts of H₂, I2, and HI. H₂(g) + I2(g) ↔ 2 HI(g) with Kc = 50.2 at 445 °C. a) [H₂] = 0.0375 mol, [I2] = 0.0375 mol, [HI] = 0.075 mol b) [H₂] = 0.075 mol, [I2] = 0.075 mol, [HI] = 0.150 mol c) [H₂] = 0.075 mol, [I2] = 0.075 mol, [HI] = 0.0375 mol d) [H₂] = 0.150 mol, [I2] = 0.150 mol, [HI] = 0.300 mol