A balloon has a volume of 10,500 liters, and the temperature is 15°C. If the temperature were -25°C, what would the volume of the balloon be? 12,194 L 9,042 L
According to Charle's law; the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure. VT= a constant V1/T1 = V2/T2 V1 = 10,500 liters, T1= 15+273 =288 K; V2= ?, T2 = -25 +273 = 242 K 10,500/288 = V2/242 V2 = (10,500 ×242)/288 = 8822,92 Liters Therefore; the new volume of the balloon will be 8823 Liters