Respuesta :

caylus
Hi,
[tex]f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\ =2-9+12-12+10-3\\ =0\\ f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\ g(x)=2x^4-7x^3+5x^2-7x+3\\ g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\ =162-189+45-21+3\\ =0\\ g(x)=(x-3)(2x^3-x^2+2x-1)\\ h(x)=2x^3-x^2+2x-1\\ h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\ =0\\ h(x)=(2x-1)(x^2+1)\\ f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\ [/tex]
Roots are 1,3,0.5,i,-i.