Nicalias7207 Nicalias7207

10-06-2018
Mathematics

contestada

What are the roots of the given power equation?
3(x-4)^4/3 + 16 = 64

A. x=12 and x = -4
B. x=12
C. x= -4
D.x= - 12 and x = 4

Respuesta :

Аноним Аноним

10-06-2018

Subtract 16 from both sides gives:-
3 (x - 4)^4/3 = 64 - 16 = 48
divide both sides by 3:-
(x - 4)^4/3 = 16
x - 4 = 16^3/4
x - 4 = 2^3 = 8

x = 12

ITs B

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