Respuesta :

The answer is B, 0.496. Hope this helps.

Answer with explanation:

[tex]\rightarrow f(x)=0.01 \times (2)^x \\\\\rightarrow f(3)=0.01 \times 2^3\\\\=0.08\\\\\rightarrow f(8)=0.01 \times 2^8\\\\=0.01 \times 256\\\\=2.56[/tex]

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          [tex]=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{f(8)-f(3)}{8-3}\\\\=\frac{2.56-0.08}{5}\\\\=\frac{2.48}{5}\\\\=0.496[/tex]  

Option B= 0.496