fudin2784 fudin2784

08-08-2018
Chemistry

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How many moles of nacl are required to make 250ml of a 3.00 m solution?

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Willchemistry Willchemistry

12-08-2018

Hey there!

Volume in liters:

250 mL / 1000 => 0.25 L

Molarity = 3.00 M

Therefore:

n = M * V

n = 3.00 * 0.25

n = 0.75 moles

hope this helps!

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