Answer:
One piece is [tex]\frac{43}{3}[/tex] inches and another piece is [tex]\frac{86}{3}[/tex] inches
Step-by-step explanation:
Let smaller piece length be [tex]s[/tex]
Let larger piece length be [tex]l[/tex]
Since total of two pieces is 43, we can write:
[tex]s+l=43[/tex]
Also, one piece is twice as long as the other (so longer piece is definitely twice as the short piece), we can write:
[tex]l=2s[/tex]
Substituting equation 2 into equation one, we can solve for s:
[tex]s+l=43\\s+(2s)=43\\3s=43\\s=\frac{43}{3}[/tex]
Thus longer piece is:
[tex]l=2s=2(\frac{43}{3})=\frac{86}{3}[/tex]
