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using hooke's law, f spring = k triangle x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is applied to it.

Respuesta :

As we know that spring force is given as

[tex]F = kx[/tex]

here we know that

F = 4 N

x = 2 cm = 0.02 m

now from the above equation we will have

[tex]4 = k(0.02)[/tex]

[tex]k = 200 N/m[/tex]

so the elastic constant of the spring will be 200 N/m

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