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Which of these is a point-slope equation of the line that is perpendicular to y-3=4(x-10) and passes through (-3,7)?

A. y+7= -1/4(x-3)
B. y-7= -1/4(x+3)
C.y+7= 4(x-3)
D.y-7= -4(x+3)

Respuesta :

MrsStrong

Answer:

B

Step-by-step explanation:

The point slope form of a line is [tex](y-y_1)=m(x-x_1)[/tex] where [tex]x_1=-3\\y_1=7[/tex]. We can find the slope which is perpendicular to the slope of 4 in the equation y=4(x-10). Perpendicular slope is the negative reciprocal which is -1/4.

We write  

[tex](y-7)=-\frac{1}{4}(x--3)\\(y-7)=-\frac{1}{4}(x+3)[/tex]

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