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In a tornado, the wind velocity in meters per second can be described by the function v(p)-12.3 1134 -3p where p is the air pressure in millibars. What is the air pressure of a tornado in which the wind velocity is 49.3 meters per second? Round your answer to the nearest whole millibar.

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The answer is 373 millibars.

In a tornado, the wind velocity in meters per second can be described by the function

 v(p)-12.3=1134 -3p

Whee,p=Pressure in Millibars

When, Wind Velocity =49.3 meters per second

We have to Calculate air Pressure.

49.3-12.3=1134-3p

37=1134-3p

3p=1134-37

3p=1097

[tex]\rightarrow p=\frac{1097}{3}\\\\p=365.67\\\\p=366\text{approx}[/tex]

So, Pressure=366 Millibar

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