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A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form. A) (x - 3)2 + (y - 8)2 = 9 B) (x + 3)2 + (y + 8)2 = 9 C) (x - 3)2 + (y - 8)2 = 64 D) (x + 3)2 + (y + 8)2 = 64

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Anonymouslizard

Answer:

Step-by-step explanation:

A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form.

A) (x - 3)2 + (y - 8)2 = 9<==2x+2y=31

B) (x + 3)2 + (y + 8)2 = 9<==2x+2y=−13

C) (x - 3)2 + (y - 8)2 <==2x+2y=86

D) (x + 3)2 + (y + 8)2 = 64<==2x+2y=42

Answer:

the answer is B

Step-by-step explanation:

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