Answer:
Explanation:
1) Write the model for the volume and base area of the rectangular sotorage container:
base width, w = x
base length, l = 2x
B = (2x) (x) = 2x²
height = h
V = 2x² h = 10 ⇒ h = 10 / (2x²)
2) Total area, A
S₁ = (x) . (h) = (x) . 10 / (2x²) = 10 / (2x) = 5 / x
S₂ = S₁ = 5 / x
S₃ = (2x) . (h) = (2x) . 10 / (2x²) = 10 / x
S₄ = S₃ = 10 / x
3) Cost
$ 10 (2x²) = 20x²
$6 (S₁ + S₂ + S₃ + S₄) = 6 (5/x + 5/x + 10/x + 10/x ) = 6 ( 30/x) = 180/x
4) Cheapest container
Minimum cost ⇒ find the minimum of the function 20x² + 180 / x, which formally is done by derivating the function and making the derivative equal to zero.
Solve to find the value of x that makes the first derivative equal to zero:
Replace x = 1.65 in the equations of costs to find the minimum cost:
That is the final answer, already rounded to the nearest cent: $163.54