Answer:
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Moles of NaOH = 8 moles
Volume of the solution = 0.5 L
[tex]Molarity=\frac{8 mol}{0.5 L}=16.0 M[/tex]
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
