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You are asked to make 43 grams of iron (Fe) from iron III oxide (Fe2O3) and carbon monoxide (CO) as shown in the chemical equation below.

Fe2O3 + 3CO → 2Fe + 3CO2

How many grams of iron III oxide must you use?

Question 10 options:

61.49 g


122.99 g


0.77 g


6863 g

Respuesta :

smmwaite

Answer:

=61.49 g

Explanation:

From the equation, we see that 1 mole of iron (III) oxide produces 2 moles of iron.

1 mole of iron (III) oxide has a mass of: (55.845×2+ 15.995×3) = 159.675 grams

43 grams into moles = 43g/55.845g/mol= 0.77 moles

If one mole of Iron (III) oxide produces 2 moles of iron, then 0.77 moles of iron is produced by:

1×0.77 moles / 2= 0.385 moles

Thus 0.385 moles has a mass of:

0. 385 moles × 159.675 grams =  61. 5 grams

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