HazP1z
contestada

Given that the first term and the common difference of an arithmetic progression are 6 and 3 respectively. Calculate the sum of all terms from 4th term to the 14th term.​

Respuesta :

Answer:

330

Step-by-step explanation:

Evaluate the sum of 14 terms and subtract the sum of the first 3 terms

The sum to n terms of an arithmetic sequence is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ], so

[tex]S_{14}[/tex] = 7 [ (2 × 6) + (13 × 3)]

                         = 7(12 + 39) = 7 × 51 = 357

[tex]S_{3}[/tex] = 6 + 9 + 12 = 27

Sum of terms from 4 th to 14 th = 357 - 27 = 330