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Daniel takes his two dogs, Pauli the Pointer and Newton the Newfoundland, out to a field and lets them loose to exercise. Both dogs sprint away in different directions while Daniel stands still. From Daniel's point of view, Newton runs due North at 3.40 m/s, but from Pauli's point of view, Newton appears to be moving at 1.10 m/s due East. What must Pauli's velocity relative to Daniel be for this to be true? Express your answer in terms of the ???? ‑ and ???? ‑components if North is the +???? ‑direction and East is the +???? ‑direction.

Respuesta :

Chenk13

Answer:

Explanation:

3.4 m/s due North, -1.1 m/s due East

onyebuchinnaji

The velocity of Pauli relative Daniel in y-direction is -3.4 m/s and in x-direction is 1.1 m/s.

The given parameters;

  • Newton's velocity from Daniels view, v₁ = 3.4 m/s North
  • Newton's velocity from Pauli's view, v₂ = 1.1 m/s East

The sketch of the Newton's velocity is presented as follows;

                                                 

                                                ↑ 3.4 m/s North

                                                ↑

                                                ↑---------→ 1.1 m/s East

For the above velocity of Newton to be true, the velocity of Pauli relative to Daniel is calculated as follows;

[tex]V_{P/D} \ \ : y-component = 0-3.4 \ m/s = -3.4 \ m/s\\\\V_{P/D} \ \ : x-component = 1.1 - 0 = 1.1 \ m/s[/tex]

Thus, the velocity of Pauli relative Daniel in y-direction is -3.4 m/s and in x-direction is 1.1 m/s.

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