fish373737 fish373737

09-09-2019
Mathematics

contestada

Describe how you would compare 3.6 and
[tex] \sqrt{12} [/tex]

Respuesta :

mani82ebra mani82ebra

09-09-2019

Step-by-step explanation:

√12=

2√3

÷2. ÷2

√3. 1.8

√3≈1.7

1.7<1.8

3.6>√12

method 2

(3.6)^2>12

Answer Link

aambrocio aambrocio

19-09-2019

Answer:

Step-by-step explanation:

How can I write it

Answer Link

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