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A daredevil is shot out of a cannon at 48.3 ◦ to the horizontal with an initial speed of 32.5 m/s. A net is positioned a horizontal distance of 32.8 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.

Respuesta :

Answer:19.09 m

Explanation:

Given

[tex]\theta =48.3^{\circ}[/tex]

initial Velocity(u)=32.5 m/s

Distance given(x)=32.8

We know equation of trajectory of Projectile is given by

[tex]y=x\tan \theta -\frac{gx^2}{2u^2cos^2\theta }[/tex]

[tex]y=32.8\times \tan 42.8-\frac{9.8(32.8)^2}{2(32.5)^2\times (cos48.3)^2}[/tex]

y=30.37-11.278=19.09 m

thus Net must be kept at a vertical distance of 19.09 m above canon

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