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A rifle is aimed horizontally at a target 30 m away. The bullet hits the target 1.9 cm below the aiming point. What are the bullet’s a. time of flight? b. speed as it emerges from the rifle? 3.

Respuesta :

Answer:0.0622 s

482.31 m/s

Explanation:

Given

target distance=30 m

Bullet hits the target 1.9 cm below

If we consider bullet motion to be projectile then

vertical distance traveled=1.9 cm

time travel to cover 1.9 cm is

[tex]h=ut+\frac{at^2}{2}[/tex]

here u is initial vertical velocity

[tex]1.9\times 10^{-2}=0+\frac{9.8\times t^2}{2}[/tex]

[tex]t^2=0.3877\times 10^{-2}[/tex]

[tex]t=0.622\times 10^{-1}=0.0622 s[/tex]

Range =30 m

[tex]30=u_x\times t[/tex]

[tex]30=u_x\times 0.0622[/tex]

[tex]u_x=482.31 m/s[/tex]

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