Answer:
B = 0.002 T
Explanation:
It is given that,
Distance between two parallel wires, d = 5 mm = 0.005
Current in each wire, I = 60 A
Let B is the magnitude of the magnetic field at a point that is between the two wires and 2.0 mm from one of the two wires. Firstly, calculating the magnetic field due to first wire is given by :
[tex]B_1=\dfrac{\mu_oI}{2\pi d}[/tex]
[tex]B_1=\dfrac{4\pi \times 10^{-7}\times 60}{2\pi \times 0.002}[/tex]
[tex]B_1=0.006\ T[/tex]
The magnetic field due to second wire is given by :
[tex]B_2=\dfrac{\mu_oI}{2\pi d}[/tex]
[tex]B_2=\dfrac{4\pi \times 10^{-7}\times 60}{2\pi \times 0.003}[/tex]
[tex]B_2=0.004\ T[/tex]
Let B is the net magnetic field from wire A, so,
[tex]B=B_1-B_2[/tex]
[tex]B=0.006-0.004[/tex]
B = 0.002 T
Hence, this is the required solution.
