Answer:
0,36π inches³ or simply 1.13 inches³
Step-by-step explanation:
In this case, first, we need to calculate the volume of the sphere with the formula:
V = 4πr³/3
Replacing the data we have:
V = 4π(3)³/3
V = 36 in³
Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:
If V = 4πr³/3
Then the derivate of V (dV) would be:
dV = 4π*3*r²/3 dr
Where dr is the error of radius so:
dV = 4π*r² dr
Solving for dV:
dV = 4*3.14*(3)²*(0.01)
dV = 1.13 in³
So at the end, we just report the volume of the sphere as
V = 36 ± 1 in³
dV =
