Answer:
The length of EB is 25 unit
Step-by-step explanation:
Given as:
ABCD is a square With diagonal AC and BD
The length of DB = 7x + 1
The length of AE = 2x + 11
The mid point of BD and AC is E
Let the each side of square be m
So, BD² = m² + m²
Or, (7x + 1) = 2 m²
Or m² = [tex]\frac{(7x + 1)}{2}[/tex]
Again
AC² = m² + m² = 2 m²
Or, AC = (7x + 1)
∵ AE is the half of diagonal AC
So, AE = [tex]\frac{1}{2}[/tex] × (7x + 1)
Or, 2x + 11 = [tex]\frac{1}{2}[/tex] × (7x + 1)
or , 4x + 22 = 7x + 1
Or, 3x = 21
∴ x = 7 unit
So, BD = 7 (7 ) + 1 = 50 unit
So, BE is the half of diagonal BD
Or, BE = [tex]\frac{1}{2}[/tex] × 50 = 25 unit
Hence The length of EB is 25 unit Answer
