Answer:
cosФ = [tex]\frac{\sqrt{11} }{6}[/tex]
Step-by-step explanation:
Given as Sin Ф = [tex]\frac{5}{6}[/tex]
And According to Pythagorean identity ,
sin²Ф + cos²Ф = 1
I,e cos²Ф = 1 - sin²Ф
Or, cosФ = √(1 - sin²Ф )
∵ sinФ = [tex]\frac{5}{6}[/tex]
So , cosФ = [tex]\sqrt{1 - (\frac{5}{6})^{2}}[/tex]
Or , cosФ =[tex]\sqrt{( 1 - (\frac{25}{36})[/tex]
Or, cosФ = [tex]\sqrt{\frac{(36-25)}{36} }[/tex]
Or, cosФ = [tex]\frac{\sqrt{11} }{6}[/tex] Answer
