Answer:
y = x2- 3x +15
Step-by-step explanation:
F'(x) = dy÷dx
=2x - 3
On integrating this function we get the function f (x)
y =( 2 x 2÷ 2) -3x +c
= x2 -3x + c
x -3 and y = 3
So 3 =( -3) × (-3) - 3 × (-3) + c
3 = 9 + 9 +c
3 = 18 + c
C = 15
Therefore the equation is
y = x2 - 3x +15
