0.918 M
Assuming the question requires we calculate the Molarity of sulfuric acid:
We are given:
We can calculate the molarity of the acid using the following steps;
The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.
Therefore, the balanced equation will be;
H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)
When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.
Number of moles = Molarity × Volume
= 1.700 M × 0.027 L
= 0.0459 moles
Thus, moles of KOH used is 0.0459 moles
From the reaction, 1 mole of the acid reacts with 2 moles of KOH
Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2
Thus, moles of H₂SO₄ = Moles of KOH ÷ 2
= 0.0459 moles ÷ 2
= 0.02295 moles
Molarity is the concentration of a solution in moles per liter
Molarity = Moles ÷ Volume
Molarity of the acid = 0.02295 moles ÷ 0.025 L
= 0.918 M
Thus, the molarity of the acid, H₂SO₄ is 0.918 M
