A stone is thrown horizontally at a speed of 19.4m/s from the top of a cliff 19.4m high. What is the horizontal distance from the base of the cliff where the stone lands?

Respuesta :

Answer:

38.218 m

Explanation:

Horizontal projectile motion is there.(graph)

applying motion equations for downward motion

(only a horizontal velocity is there. stone is subjected to the gravity )

Sv = height

u = initial velocity

t= time taken

[tex]S_v=ut+\frac{1}{2}*at^{2}  \\19.4=0+\frac{1}{2}*10*t^{2}  \\t=1.97 s[/tex]

for horizontal motion

Sh= horizontall distance

[tex]S_h=ut\\s=19.4*1.97\\s=38.218 m[/tex]

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