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Three perfectly polarizing sheets are spaced 2?cm {\rm cm} apart and in parallel planes. The transmission axis of the second sheet is 28 ? \deg relative to the first one. The transmission axis of the third sheet is 90 ? ^\circ relative to the first one. Unpolarized light impinges on the first polarizing sheet.

What percent of this light is transmitted out through the third polarizer?

Respuesta :

Answer:

I₃/Io % = 0.8.59

Explanation:

A polarizer is a complaint sheet for light in the polarization direction and blocks the perpendicular one. When we use two polarizers the transmission between them is described by Malus's law

      I = I₀ cos² θ

Let's apply the previous exposures in our case, the light is indicatively not polarized, so the first polarized lets half of the light pass

      I₁ = ½ I₀

The light transmitted by the second polarizer

     I₂ = I₁ cos²  θ

     I₂ = (½ I₀) cos2 28

The transmission by the polarizing  third is

     I₃ = I₂ cos²  θ₃    

The angle of the third polarizer with respect to the second is

     θ₃ = 90-28

      θ₃ = 62º

I₃ = (½ I₀ cos² 28 cos² 62)

Let's calculate

I₃ = Io ½ 0.7796 0.2204

I₃ = Io 0.0859

I₃/Io= 0.0859    100

I₃/Io % = 0.8.59

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