Calculate the lattice energy for NaF (s) given the following

sublimation of energy +109 kj/mol

Hf for F (g) + 77 kj/mol

first ionization energy of Na (g) +495

electron affinity of F(g) -328

enthalpy of formation of NaF(s) -570 kj/mol

A. -177

B. 192

C. -804

D. -1047

E. -923

Respuesta :

Answer: E

Explanation:

The lattice energy is the energy change when one mole of a crystal is formed from its components ions in its gaseous sate

Therefore lattice energy = heat of Sublimation+ ionization energy +electron affinity-(heat of formation)

Therefore lattice Energy =     109 +495 -328 +570.

Lattice energy = --923kjmol-1