contestada

A thin wire has the shape of the quarter circle in the first quadrant. The circle is centered at the origin with radius a. Let rho = kxy be the linear density of the wire. Here k > 0 is just a constant. Find the mass and the center of mass of the wire

Respuesta :

Answer:

mass =[tex]\frac{k*a^{3} }{2}[/tex]

COM of arc ([tex]\frac{2a}{3}[/tex],[tex]\frac{2a}{3}[/tex])

Explanation:

By using cylendrical coordinate system find total mass and COM position.

This arc is symmetric about x=y thus COM lies on this line.

Rest is in attachment.

Ver imagen ZealousSheridan

Otras preguntas