The "penetration of the bullet" is 5 m
Explanation:
A "bullet" with "kinetic energy" of = 400J
A resistive force stops the bullet = 8.00 x 10 N
Work = change in energy
Work = ∆ Kinetic Energy (equation 1)
Work = [tex]F\times d[/tex] (equation 2)
From equations 1 and 2 we have,
[tex]F\times d[/tex] = ∆ Kinetic Energy
Where
,
Kinetic Energy = 400 J
F = 8.00 x 10 N
(8.00 x 10 N) d = 400 J
(80 N) d = 400 J
[tex]d=\frac{400}{80}[/tex]
d = 5 m
The penetration of the bullet is 5 m
