Answer:
130.56 mg
Step-by-step explanation:
The equation might be written incorrectly. Given that for a heavier dog, a higher dosage is required, the equation that describes the dosage in milligrams of a heartworm preventive for a dog who weighs x pounds is:
[tex]D(x) = \frac{136}{25}x[/tex]
If a dog weighs 24 pounds, than the dosage required for this dog is:
[tex]D(24) = \frac{136}{25}*24\\D(24) = 130.56\ mg[/tex]
