Answer:
[tex]\alpha = 5.27 rad/s^2[/tex]
Explanation:
Given data:
m = 12.5 kg
distance[tex] r_w = 28.0 cm = 0.28 m[/tex]
I = 0.900 kg m^2
force = 1475 N
lever arm [tex]= 3.00 cm = 0.03 m[/tex]
[tex]tau_{net} = I \alpha [/tex]
[tex]\alpha = \frac{\tau_{net}}{I}[/tex]
[tex]\alpha = \frac{F r_m - F_w r_w}{I + m r_w^2}[/tex]
[tex]\alpha = \frac{1475 \times 0.03 - 12.5b\times 9.81 \times 0.28}{0.900 + (12.5 \times 0.28^2)}[/tex]
[tex]\alpha = 5.27 rad/s^2[/tex]
