Answer:
m= 5.3658 x 10³ g
Explanation:
Given that
Energy eat each day = 2897 cal
Energy consume each day ,Q = 1.21268 x 10⁷ J
Latent heat ,LH = 2.26 x 10 ⁶ kg/J
Lets take , the mass of the water vaporize = m kg
From energy balance
Q = m x LH
1.21268 x 10⁷ = 2.26 x 10 ⁶ x m
[tex]m=\dfrac{ 1.21268\times 10^{7}}{2.26\times 10^{6}}\ kg[/tex]
m =5.3658 kg
m= 5.3658 x 10³ g
Therefore the mass of the water is 5.3658 x 10³ g.
