Answer:
[tex]\large\boxed{b=-\dfrac{62}{45}}[/tex]
Step-by-step explanation:
[tex]-45b+5=67\qquad\text{subtract 5 from both sides}\\\\-45b+5-5=67-5\\\\-45b=62\qquad\text{divide both sides by (-45)}\\\\\dfrac{-45b}{-45}=\dfrac{62}{-45}\\\\b=-\dfrac{62}{45}[/tex]
