Answer:150 N
Explanation:
Given
Force applied at one end of lever is [tex]F_1=50\ N[/tex]
Distance moved is [tex]d_1=d[/tex]
Distance moved on other end is [tex]d_2=\frac{d}{3}[/tex]
work done by the force is given by
[tex]W=F\cdot d[/tex]
[tex]W=F_1\cdot d_1=F_2\cdot d_2[/tex]
[tex]F_2=\frac{d_1}{d_2}\cdot F_1[/tex]
[tex]F_2=\frac{3d}{d}\cdot 50[/tex]
[tex]F_2=150\ N[/tex]
