Suppose we have a 12.2-L sample containing 0.50 mol oxygen gas (O2) at a pressure of 1 atm and a temperature of 25oC. If all this O2 were converted to ozone (O3) at the same temperature and pressure, what would be the volume of the ozone

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Answer:

f all this O₂ were converted to ozone (O₃) at the same temperature and pressure, the volume of the ozone will be:

8.1 L

Explanation:

The Avogadro Law states that:

V₁ / n₁ = V₂ / n₂ ----- (1)

Given that:

V₁ = 12.2 L

V₂ = ?

n₁ = 0.5 mol

n₂ = ?

The chemical equation of the conversion is as follow:

3  O₂  ⇒ 2 O₃

so putting the values in the above equation no. 1

12.2 / 3 = V₂ / 2

V₂ = (12.2 x 2) / 3

V₂ = 8.1 L

Answer:

Ozone is an inorganic molecule with a chemical formula as O3 . Ozone is found throughout the troposphere and the stratosphere . If all the oxygen O2 molecules are converted to ozone O3 at the same temperature and pressure  then the volume of the ozone will be 8.1 L

Explanation:

For computation for the volume of ozone , we need to use the Avogadro law .

These law states that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules.

Here ,

Volume of O2 is given as 12.2 L

Volume of  O3  = ?

First amount of gas is given as 0.50 molecule

Second amount of gas = ?

The chemical equation of the conversion  3 O2 = 2 O3

So , finding the volume of ozone the formula is :

[tex]\begin{aligned}\frac{\text{Volume}\;1}{\text{Amount of Gas}\;1}&=\frac{\text{Volume}\;2}{\text{Amount of Gas}\;2}\\\frac{12.2}{3}&=\frac{V2}{2}\\V2&=\frac{12.2\times2}{3}\\V2&=8.1\;\text{L}\end{aligned}[/tex]

Therefore , the volume of ozone at the same temperature and pressure will be 8.1 L .

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