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Larry drops a 5kg ball off of a building. The ball hits the ground 4.7s later. How tall is the building?

Respuesta :

MathPhys

Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 4.7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (4.7 s) + ½ (9.8 m/s²) (4.7 s)²

Δy ≈ 110 m

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