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A force F acts in the forward direction on a cart of mass m. A friction force/opposes this motion. (a) Use Newton’s second law and show that the acceleration of the cart is (F−f)/m. (b) If the cart’s mass is 4.0 kg, the applied force is 12.0 N, and the friction force is 6.0 N, show that the cart’s acceleration is 1.5 m/s2.

Respuesta :

Answer:

Explanation:

It is given that cart is accelerating therefore a net force is acting on the cart which is accelerating it.

If F is the applied force and f is the friction force then acceleration is given by

[tex]F-f=ma[/tex]

[tex]a=\frac{F-f}{m}[/tex]

(ii)If

mass [tex]m=4\ kg[/tex]

[tex]F=12\ N[/tex]

[tex]f=6\ N[/tex]

acceleration [tex]a=1.5\ m/s^2[/tex]

acceleration is given by [tex]a=\frac{F-f}{m}[/tex]

[tex]a=\frac{12-6}{4}=\frac{6}{4}=1.5\ m/s^2[/tex]                                                    

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