Respuesta :
Explanation:
The given data is as follows.
Length of molecule = [tex]11^{o}A[/tex] = [tex]11 \times 10^{-8} cm[/tex]
(as 1 cm = [tex]10^{8}^{o}A[/tex])
Density = 0.92 [tex]g/cm^{3}[/tex]
Diameter of watch glass = 5.25 cm
Hence, radius will be calculated as follows.
r = [tex]\frac{5.25}{2}[/tex]
= 2.625 cm
(a) Now, we will calculate the area of watch glass as follows.
Area = [tex]\pi r^{2}[/tex]
= [tex]3.14 \times (2.625)^{2}[/tex]
= [tex]3.14 \times 6.8906[/tex]
= 21.636 [tex]cm^{2}[/tex]
Minimum thickness of molecule will be used for the formation of monolayer.
Thickness of layer = length of molecule = [tex]11 A^{o}[/tex]
(b) Now, we will calculate the volume of monolayer as follows.
Volume = Area × Length
= [tex]21.636 cm^{2} \times 11 \times 10^{-8}[/tex]
= [tex]238 \times 10^{-8} cm^{3}[/tex]
Hence, volume of the monolayer is [tex]238 \times 10^{-8} cm^{3}[/tex].
(c) Mass of monolayer will be calculated as follows.
Mass of monolayer = volume × density
= [tex]238 \times 10^{-8} cm^{3} \times 0.92[/tex]
= [tex]218.96 \times 10^{-8} g[/tex]
= [tex]2.18 \times 10^{-6} g[/tex]
Hence, the mass of monolayer is [tex]2.18 \times 10^{-6} g[/tex].
