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If the moment of inertia of the diver in a straight position is 14 kgâ‹…m2 and in a tucked position is 4.0 kgâ‹…m2 , by what factor is her angular velocity when tucked greater than when straight?\

Respuesta :

Answer:

required factor of angular velocity is 3.5

Explanation:

given data

I straight = 14 kg.m²

I' tucked = 4 kg.m²

solution

as here by the conservation of angular momentum we get

I straight = I tucked  .................1

I × ω = I' × ω'  

[tex]\frac{\omega '}{\omega } = \frac{I}{I'}[/tex]  

[tex]\frac{\omega '}{\omega } = \frac{14}{4}[/tex]

[tex]\frac{\omega '}{\omega } = 3.5[/tex]  

required factor of angular velocity is 3.5

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