Answer:
As per previous submission, the map distance between Wx & V is 7 mu and Sh & V is 30 mu.
Coefficient of coincidence = No. of observed double cross overs / No. of Expected double cross overs
Expected double cross overs frequency = product of single cross over frequencies (map distance / 100 = frequency)
= 0.07 x 0.3 = 0.021
Number of expected double cross overs = 0.021 x Total progeny = 0.021 x 10,756 = 225.8
So Coefficient of coincidence = (87+94) / 225.8
= 0.8
Then Interference - 1- Coefficient of coincidence = 1-0.8 = 0.2
answer is A