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A kicker kicks the football for an extra point after a touchdown. The football leaves the kicker’s foot with a vertical velocity of 18 m/s and a horizontal velocity of 15 m/s. (d) If the football is instead punted, such that it is kicked 1m above the ground, what horizontal distance will the football travel (in m)?

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onyebuchinnaji

Answer:

The horizontal distance the football will travel is 1.8 m

Explanation:

Given;

vertical velocity Vy = 18 m/s

horizontal velocity Vx = 15 m/s

vertical distance traveled by the football = 1 m

To determine the horizontal distance traveled by the football, after been kicked 1 m above the ground, we apply equation of motion to determine the time spent by the football in the air before hitting the ground.

[tex]y = v_y t+ \frac{1}{2}gt^2 \\\\1 = 18t+4.9t^2\\\\4.9t^2 +8t-1 =0\\\\t = 0.12 s[/tex]

Horizontal distance, [tex]X = v_xt[/tex]

X = 15*0.12 = 1.8 m

Therefore, the horizontal distance the football will travel is 1.8 m

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