Respuesta :

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=\stackrel{area~of}{its~base}\\ h=height\\[-0.5em] \hrulefill\\ B=10\\ h=12 \end{cases}\implies V=\cfrac{1}{3}(10)(12)\implies V=40[/tex]