The area of a rectangle is given as 8cm^2, correct to the nearest cm^2.

The lower bound of the area is 7.5cm^2

The width of the rectangle is given as 2 cm, correct to the nearest cm.

Calculate the lower bound for the length of the rectangle.​

Respuesta :

Answer:

3.5cm

Step-by-step explanation:

The area of a rectangle is the product of the length and width.

It was given that, the area of the rectangle is 8cm² to the nearest cm²

The width of the rectangle is given as 2 cm, correct to the nearest cm.

This means that:

[tex]l \times 2 = 8[/tex]

Divide both sides by 2 to get:

[tex]l = \frac{8}{2} [/tex]

[tex]l = 4cm[/tex]

Since with was to the nearest cm, so is the length.

To find the lower bound we divide the level of accuracy by 2 and subtract from 4.

[tex]lower \: bound = 4 - \frac{1}{2} = 3.5 [/tex]

Therefore the lower bound for the width of the rectangle is 3.5cm