Question:
The complete figure of question is attached below
Answer:
The cup can hold 94.2 [tex]cm^3[/tex] or [tex]30 \pi\ cm^3[/tex] of water
Solution:
Given that,
Diameter = 6 cm
[tex]Radius = \frac{diameter}{2}\\\\Radius = \frac{6}{2}\\\\Radius = 3\ cm[/tex]
Also,
Height = 10 cm
The volume of cone is given as:
[tex]V = \frac{1}{3} \times \pi \times r^2 \times h[/tex]
Where,
"r" is the radius and "h" is the height
Substituting the values we get,
[tex]V = \frac{1}{3} \times \pi \times 3^2 \times 10\\\\V = \pi \times 3 \times 10\\\\V = 30 \pi\\\\V = 30 \times 3.14\\\\V = 94.2\ cm^3[/tex]
Thus the volume of cup is 94.2 [tex]cm^3[/tex] or [tex]30 \pi\ cm^3[/tex]
