Answer:
a. Time=25seconds
b.distance=1041.67m
Explanation:
a.The equation for [tex]D[/tex] in terms of m/s is [tex]\frac{250}{3}m/s[/tex] after conversion.
To find when speed reaches 300km/hr=83.33m/s, we find [tex]D\prime[/tex] and solve for [tex]t[/tex]
[tex]D=\frac{5}{3}t^2\\D\prime=\frac{5}{3}(2t)=\frac{10}{3}t=\frac{250}{3}\\t=25sec[/tex]
b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.
#To find distance travelled in that time , we substitute for[tex]t=25[/tex] in our distance equation:
[tex]D(25)=\frac{5}{3}(25)^2\\=1041.67m[/tex]
Hence the distance of the plane before it gets airborne is 1041.67m
