Answer:
0.3436
Step-by-step explanation:
Answer:
61.57
Step-by-step explanation:
Number of strikes (n) = 600 strikes
Number of critical strikes (X) = 237 strikes
Z-score for a 99% confidence interval (Z) = 2.576
The proportion of critical strikes (p) is:
[tex]p = \frac{237}{600}\\p=0.395[/tex]
The lower confidence bound (L) for a confidence interval of a proportion is determined by the following expression
[tex]L= p - Z*\sqrt{\frac{p*(1-p)}{n}}[/tex]
Applying the given data:
[tex]L= 0.395 - 2.576*\sqrt{\frac{0.395*(1-0.395)}{600}} \\L=0.3436[/tex]
The lower confidence bound for the proportion of strikes that are critical strikes is 0.3436