A circular tank that has a diameter of 12 m and sides that are 8 m high contains water with a depth of 5 m. How much work (in Joules) is required to pump all of the water to a point that is 4 meters above the top of the tank

Respuesta :

Answer:

= 58,189,950J

Explanation:

Work done in pumping all the water:

Average height of the pool,

[tex]h = \frac{H + D}{2}[/tex]

[tex]h = \frac{8 + 5}{2} \\= 6.5[/tex]

Volume of water

[tex]V = \pi r^{2}h = \pi \times 6^{2}\times 5 \\= 565.5\ m^{3}[/tex]

Mass of water

[tex]m_{w} = \rho_{w} \times V\\ = 1000 \times 565.5\\= 565,500kg[/tex]

Work done is given by the potential energy of the water as

[tex]W = m_{w}gh \\= 565,500\times 9.8\times 6.5 \\\\= 58,189,950\ J[/tex]